by Wayne » Tue Mar 23, 2010 8:10 pm
"Obliteration" is a lot more difficult than you might think.
You basically need to take every atom with in it and give them enough energy to defeat gravity and reach infinity: Gravitational binding energy. This can be estimated without scary mathematics by assuming an object is a uniformly dense sphere. Obviously not correct, but it's in the right order of magnitude for a solid body and within a few orders of magnitude for stars. The equation is:
U = (3GM^2)/5r
Where:
U = gravitational binding energy
G = Gravitational constant
M = Mass
r = radius
For one solar mass with one solar diameter (2E30 kg and 7E8 km) and a value for G of 6.7E-11 we work out that U is equal to 2.3E41 joules. (Text gives it as 1.2E44, stars are not good examples to use for the simplified equation, but planets are)
Okay, so how much energy does a supernova have? We measure that in ergs, it's a more convenient unit, but ergs is easily convertable to joules. 1E54 ergs, a typical supernova, is 1E48 joules.
So if the Sun were close enough to a supernova, it would, by our first-order estimations, have a chance of being entirely disrupted. It would need to absorb one ten thousandth of the supernova's output. The inverse square law (feel free to go calculate it) ensures the Sun would have to be ungodly close to the supernova to have a chance of absorbing that much energy.
"Obliteration" is a lot more difficult than you might think.
You basically need to take every atom with in it and give them enough energy to defeat gravity and reach infinity: Gravitational binding energy. This can be estimated without scary mathematics by assuming an object is a uniformly dense sphere. Obviously not correct, but it's in the right order of magnitude for a solid body and within a few orders of magnitude for stars. The equation is:
U = (3GM^2)/5r
Where:
U = gravitational binding energy
G = Gravitational constant
M = Mass
r = radius
For one solar mass with one solar diameter (2E30 kg and 7E8 km) and a value for G of 6.7E-11 we work out that U is equal to 2.3E41 joules. (Text gives it as 1.2E44, stars are not good examples to use for the simplified equation, but planets are)
Okay, so how much energy does a supernova have? We measure that in ergs, it's a more convenient unit, but ergs is easily convertable to joules. 1E54 ergs, a typical supernova, is 1E48 joules.
So if the Sun were close enough to a supernova, it would, by our first-order estimations, have a chance of being entirely disrupted. It would need to absorb one ten thousandth of the supernova's output. The inverse square law (feel free to go calculate it) ensures the Sun would have to be ungodly close to the supernova to have a chance of absorbing that much energy.