by astro_uk » Thu Sep 21, 2006 4:04 pm
I would guess that they simply used a telecope with a filter to cut out most of the light.
The objects themselves are actually a reasonable size in astronomical terms, if we take the space station to be 100m across and located 550km away then it subtends an angle of 0.01 degrees (or a 50th of the solar diameter). In astronomy numbers that is a very reasonable 36 arcseconds across, very simple with to resolve with a big telescope.
In fact from the picture we can estimate the size of the telescope used, the resolving power of a telescope is given by 1.22 x wavelength / Diameter of the telescope. This all equals the separation of two objects in radians that can just be resolved.
So rearranging and converting the formular into arcseconds from radians gives
diameter of telescope = (252000 * wavelength) / theta
Now actually we can resolve things in that image that are about 20m across on the ISS, the wings for instance, which therefore are about 7.5 arcseconds across. If we assume the light is about 5000nm in the visible and a nice round number.
We get that the telescope is
(252000 * (5000 *10^(-9))) / 7.5 = 0.17m or 17cm across, pretty standard for an amateur scope.
I would guess that they simply used a telecope with a filter to cut out most of the light.
The objects themselves are actually a reasonable size in astronomical terms, if we take the space station to be 100m across and located 550km away then it subtends an angle of 0.01 degrees (or a 50th of the solar diameter). In astronomy numbers that is a very reasonable 36 arcseconds across, very simple with to resolve with a big telescope.
In fact from the picture we can estimate the size of the telescope used, the resolving power of a telescope is given by 1.22 x wavelength / Diameter of the telescope. This all equals the separation of two objects in radians that can just be resolved.
So rearranging and converting the formular into arcseconds from radians gives
diameter of telescope = (252000 * wavelength) / theta
Now actually we can resolve things in that image that are about 20m across on the ISS, the wings for instance, which therefore are about 7.5 arcseconds across. If we assume the light is about 5000nm in the visible and a nice round number.
We get that the telescope is
(252000 * (5000 *10^(-9))) / 7.5 = 0.17m or 17cm across, pretty standard for an amateur scope.