by rstevenson » Tue Jan 24, 2023 12:09 pm
When I saw this image a few minutes ago, my initial reaction was that the star was much too small in the sky.
Our Sun appears to be about 1/2° in diameter, if memory serves. We are, by definition, 1 AU away from our Sun which is 1 M☉ in radius. The equivalent figures for this exoplanet are 0.0206 AU and 0.2789±0.0014 R☉. A more knowledgeable person than I can probably use those figures to calculate how many degrees wide the star would be in the sky of the exoplanet. I gave it a try, taking the inverse of each of those figures (since I am comparing them to 1 AU and 1 M☉) and multiplying by 1/2°, …
(1/0.0206) (1/0.2789) (1/2°) = 1.52°
If that’s the right way to do it, then the star should appear to be about 3 times the size of our Sun, given an equivalent viewing angle on each planet. So now I think the AI illustrated the star much too large, as opposed to my initial reaction. But I’ve no idea if that calculation I just did is correct. Can someone check that for me, please?
—————- a few minutes pass —————
ACK! Found a mistake already. The answer 1.52 is in radians, not degrees. It should be 87°, according to Wolfram Alpha (which knows a great deal more than I about how to calculate.) Of course, garbage in, garbage out, so it remains to see if what I calculated makes sense. If it does, then the star should be much larger in the sky.
Rob
When I saw this image a few minutes ago, my initial reaction was that the star was much too small in the sky.
Our Sun appears to be about 1/2° in diameter, if memory serves. We are, by definition, 1 AU away from our Sun which is 1 M☉ in radius. The equivalent figures for this exoplanet are 0.0206 AU and 0.2789±0.0014 R☉. A more knowledgeable person than I can probably use those figures to calculate how many degrees wide the star would be in the sky of the exoplanet. I gave it a try, taking the inverse of each of those figures (since I am comparing them to 1 AU and 1 M☉) and multiplying by 1/2°, …
(1/0.0206) (1/0.2789) (1/2°) = 1.52°
If that’s the right way to do it, then the star should appear to be about 3 times the size of our Sun, given an equivalent viewing angle on each planet. So now I think the AI illustrated the star much too large, as opposed to my initial reaction. But I’ve no idea if that calculation I just did is correct. Can someone check that for me, please?
—————- a few minutes pass —————
ACK! Found a mistake already. The answer 1.52 is in radians, not degrees. It should be 87°, according to Wolfram Alpha (which knows a great deal more than I about how to calculate.) Of course, garbage in, garbage out, so it remains to see if what I calculated makes sense. If it does, then the star should be [i]much[/i] larger in the sky.
Rob