by VictorBorun » Mon Apr 11, 2022 5:38 am
Devil Particle wrote: ↑Fri Apr 08, 2022 4:45 pm
I bet if you took a straight line from left to right through the center of this image there would be at least 10,000 stars. So if the width of the image is 300ly, that would make the stars less than 0.03 ly apart from each other. Which is only like 2 hundred billion miles between stars. And I'm sure some of them are much closer than that!
The stars, clusters and other objects of M24 form a portion of a spiral arm (the Sagittarius or Sagittarius-Carina arm) which fills a space of significant depth, at a distance of 10,000 to 16,000 light-years.
If we want to evaluate the density of the stellar population, we need to count all the stars in the window and divide the number by 6000 ly depth × 300 ly width × 200 ly height.
If we want to evaluate the mean distance between the neighbours, we need to calculate ∛(the volume, occupied by one star) = 1/∛(the density of the stellar population).
Let us compare this with 2D calculations. If we want to evaluate the 2D density of the stellar population, we need to count all the stars in the window and divide the number by 300 ly width × 200 ly height.
If we want to evaluate the mean 2D distance between the neighbours, we need to calculate √(the area, occupied by one star) = 1/√(the 2D density of the stellar population).
So the mean distance can be expressed as ∛((the mean 2D distance between the neighbours)² × 6000 ly depth).
So if we set the mean 2D distance between the neighbours to 0.03 ly, we get the mean distance of ∛((0.03 ly)² × 6000 ly depth) = ∛(5.4 ly³) = 1,8 ly.
That would be 2 times closer than Sun to Alpha Centauri.
Nothing close to shockingly small value of 0.03 ly
[quote="Devil Particle" post_id=321929 time=1649436353 user_id=129738]
I bet if you took a straight line from left to right through the center of this image there would be at least 10,000 stars. So if the width of the image is 300ly, that would make the stars less than 0.03 ly apart from each other. Which is only like 2 hundred billion miles between stars. And I'm sure some of them are much closer than that!
[/quote]
[url="http://www.messier.seds.org/m/m024.html"]The stars, clusters and other objects of M24 form a portion of a spiral arm (the Sagittarius or Sagittarius-Carina arm) which fills a space of significant depth, at a distance of 10,000 to 16,000 light-years.[/url]
If we want to evaluate the density of the stellar population, we need to count all the stars in the window and divide the number by 6000 ly depth × 300 ly width × 200 ly height.
If we want to evaluate the mean distance between the neighbours, we need to calculate ∛(the volume, occupied by one star) = 1/∛(the density of the stellar population).
Let us compare this with 2D calculations. If we want to evaluate the 2D density of the stellar population, we need to count all the stars in the window and divide the number by 300 ly width × 200 ly height.
If we want to evaluate the mean 2D distance between the neighbours, we need to calculate √(the area, occupied by one star) = 1/√(the 2D density of the stellar population).
So the mean distance can be expressed as ∛((the mean 2D distance between the neighbours)² × 6000 ly depth).
So if we set the mean 2D distance between the neighbours to 0.03 ly, we get the mean distance of ∛((0.03 ly)² × 6000 ly depth) = ∛(5.4 ly³) = 1,8 ly.
That would be 2 times closer than Sun to Alpha Centauri.
Nothing close to shockingly small value of 0.03 ly