by TheNavigator » Mon Feb 25, 2013 11:23 pm
Now this was a perfect challenge! First, the plane. My educated guess is 2 engine Boeing, because rather of rather thin contrail. The way to go would be using plastic models of Airbus and Boeing and do a "best fit" from pictures, well, just eyeball fit might be enough.
Then the difficult one. Not so difficult. Enough hints: Australia, New South Wales, so maybe Sydney? Then the date. There is only one possible, 18 Feb 2013. Why, from the
position of Jupiter by the Moon, time, about 12.52 UTC.
Using nice free Stellarium program we find that in Sydney Moon was at an app altidude of 5 deg 44 min and Az was 299 deg 30 min.
And then ? Moon app diameter was 29 min 38 sec of arc, equals 0.4939 deg. I measured the Moon diameter from screen, got 310 mm. Same scale, aircraft was
21 mm, so 21/310* 0.4939 = 0.0335 deg, which is 0 deg 20 min 0f arc. Now You need the aircraft length, and You get the distance. No time for stupid "exactness" so
I gues a lenght of 30 m, and get distance of 51 km or 32 Stat Miles. At this point I lost my interest (it is deep night here in Finland) and leave rest for somebody else.
By the way, Stellarium is not quite correct and it is not possible to find the time exactly, because program shows Jupiter missing Moon lower limb.
Their refraction calculation is not very good (when they finally tackled it, and is it wrong way in Sout Lats ?).
Now this was a perfect challenge! First, the plane. My educated guess is 2 engine Boeing, because rather of rather thin contrail. The way to go would be using plastic models of Airbus and Boeing and do a "best fit" from pictures, well, just eyeball fit might be enough.
Then the difficult one. Not so difficult. Enough hints: Australia, New South Wales, so maybe Sydney? Then the date. There is only one possible, 18 Feb 2013. Why, from the
position of Jupiter by the Moon, time, about 12.52 UTC.
Using nice free Stellarium program we find that in Sydney Moon was at an app altidude of 5 deg 44 min and Az was 299 deg 30 min.
And then ? Moon app diameter was 29 min 38 sec of arc, equals 0.4939 deg. I measured the Moon diameter from screen, got 310 mm. Same scale, aircraft was
21 mm, so 21/310* 0.4939 = 0.0335 deg, which is 0 deg 20 min 0f arc. Now You need the aircraft length, and You get the distance. No time for stupid "exactness" so
I gues a lenght of 30 m, and get distance of 51 km or 32 Stat Miles. At this point I lost my interest (it is deep night here in Finland) and leave rest for somebody else.
By the way, Stellarium is not quite correct and it is not possible to find the time exactly, because program shows Jupiter missing Moon lower limb.
Their refraction calculation is not very good (when they finally tackled it, and is it wrong way in Sout Lats ?).