by Bravo4707 » Mon Mar 02, 2009 11:44 pm
Interesting picture and a good selection for APOD. Someone had to be pretty quick to catch it on film! (It's the 1970s.)
The comment in the caption describes the effect of the meteor passing through the earth's atmosphere and then returning to space as like a stone skipping off a lake. Perhaps a better description is the meteor punching through the atmosphere and departing, having missed the earth.
True, the atmosphere increases in density with decreasing altitude (let's say, distance toward the earth's center). However, the resultant outward force from differential drag on the top and bottom of the meteor should be extremely small, and should be overwhelmed by the force of gravity pulling the meteor toward the earth's center. The atmosphere goes from 1 ATM to zero in about 100,000 m (100 km), so the gradient of density across the leading face of a 3 meter crossection projectile is very small. Even with very turbulent drag, the differential outward force (away from earth's center) should be orders of magnitude less than the force of gravity.
If so, then the meteor will actually curve its path toward the earth's center (like a falling stone), rather than curve away from earth's center (like a skipping stone) while it is in transit through the atmosphere. BTW, the loss of speed from drag force has nothing to do with this effect. After all, the skipping stone is slowed by the surface of the water, but still manages to change direction upward.
I haven't gone through the calculations, so these comments amount to a thought experiment. I'd be interested to see someone actually calculate the difference in outward and inward forces from differential drag versus gravity. My guess is at least several orders of magnitude in favor of gravity!
Interesting picture and a good selection for APOD. Someone had to be pretty quick to catch it on film! (It's the 1970s.)
The comment in the caption describes the effect of the meteor passing through the earth's atmosphere and then returning to space as like a stone skipping off a lake. Perhaps a better description is the meteor punching through the atmosphere and departing, having missed the earth.
True, the atmosphere increases in density with decreasing altitude (let's say, distance toward the earth's center). However, the resultant outward force from differential drag on the top and bottom of the meteor should be extremely small, and should be overwhelmed by the force of gravity pulling the meteor toward the earth's center. The atmosphere goes from 1 ATM to zero in about 100,000 m (100 km), so the gradient of density across the leading face of a 3 meter crossection projectile is very small. Even with very turbulent drag, the differential outward force (away from earth's center) should be orders of magnitude less than the force of gravity.
If so, then the meteor will actually curve its path toward the earth's center (like a falling stone), rather than curve away from earth's center (like a skipping stone) while it is in transit through the atmosphere. BTW, the loss of speed from drag force has nothing to do with this effect. After all, the skipping stone is slowed by the surface of the water, but still manages to change direction upward.
I haven't gone through the calculations, so these comments amount to a thought experiment. I'd be interested to see someone actually calculate the difference in outward and inward forces from differential drag versus gravity. My guess is at least several orders of magnitude in favor of gravity!